15-18.67x+4x^2=0

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Solution for 15-18.67x+4x^2=0 equation:



15-18.67x+4x^2=0
a = 4; b = -18.67; c = +15;
Δ = b2-4ac
Δ = -18.672-4·4·15
Δ = 108.5689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18.67)-\sqrt{108.5689}}{2*4}=\frac{18.67-\sqrt{108.5689}}{8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18.67)+\sqrt{108.5689}}{2*4}=\frac{18.67+\sqrt{108.5689}}{8} $

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